1.

A block of wood of volume 25cm^(3) floats on water with 20cm^(3) of its volume immersed. Calculate (i) the density, and (ii) the weight of block of wood.

Answer»

Solution :Given: volume of block `V=25cm^(3)`
Volume immersed in WATER `v=20cm^(3)`
(i) If DENSITY of wood is `rho g cm^(-3)` then by PRINCIPLE of floatation.
Weight of block of wood = Weight of water DISPLACED by the immersed part of block.
`V rho g=vxx1xxg`(since density of water `=1gcm^(-3)`)
`:. rho=v/(V=2)/25=0.8gcm^(-3)`
(ii) Weight of block of wood `=V rho g`
`=25xx0.8xxg=20g` dyne
`=20` gf


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