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A block of wood of volume 25cm^(3) floats on water with 20cm^(3) of its volume immersed. Calculate (i) the density, and (ii) the weight of block of wood. |
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Answer» Solution :Given: volume of block `V=25cm^(3)` Volume immersed in WATER `v=20cm^(3)` (i) If DENSITY of wood is `rho g cm^(-3)` then by PRINCIPLE of floatation. Weight of block of wood = Weight of water DISPLACED by the immersed part of block. `V rho g=vxx1xxg`(since density of water `=1gcm^(-3)`) `:. rho=v/(V=2)/25=0.8gcm^(-3)` (ii) Weight of block of wood `=V rho g` `=25xx0.8xxg=20g` dyne `=20` gf |
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