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A blube emits light of `lambda = 4500 Å`. The bulb is rated as 150 watt and `8%` of the energy is emitted as light. Number of photons emitted by bulb per second is : `["Take" hc = 12400 eVÅ]` |
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Answer» Energy emitted per second by the bulb `=150xx(8)/(100)J` Energy of 1 photon `=(hc)/(lamda)=(6.626xx10^(-34)xx3xx10^(8))/(4500xx10^(-10))` Let n photons be evolved per second. `thereforenxx4.42xx10^(-19)=150xx(8)/(100)` `n=27.2xx10^(18)` |
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