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A body is falling from a height h. After it has fallen a height (h)/(2), it will possess :

Answer»

only POTENTIAL energy
only kinetic energy
half potential and half kinetic energy
more kinetic and LESS potential energy

Solution :At a height H, PE = mgh At a height `h//2,PE = MG ((h)/(2)) = (1)/(2)mgh` The rest `((1)/(2) mgh)` of the PE is converted into KE. Thus, at a height `(h//2), PE = KE = (1)/(2)mgh.`


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