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A body is moving with a constant acceleration of 11î + 7ĵ, starting from the origin. What will be the position of the body after 10s?(a) 550î + 350ĵ(b) 350î + 550ĵ(c) 350î – 550ĵ(d) 550î – 350ĵThe question was asked at a job interview.My question is from Motion in a Plane with Constant Acceleration in portion Motion in a Plane of Physics – Class 11

Answer»

Correct answer is (a) 550î + 350ĵ

To explain: The BODY’s DISPLACEMENT is GIVEN by s = (1/2)at^2. The body starts from the ORIGIN hence, the total displacement is the final position of the body. Therefore, after putting in the values, we get, s = (1/2)(11î + 7ĵ)*10^2 = 550î + 350ĵ.



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