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A body moves from point A (3,6) to point B (11,12) to point C (15,15). What is the average speed of the body along the given path if the total time taken is 100s?(a) 0.15 units/s(b) 1.5 units/s(c) 15 units/s(d) 0.0015 units/sI have been asked this question in a national level competition.My question is based upon Motion in a Plane with Constant Acceleration in portion Motion in a Plane of Physics – Class 11 |
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Answer» CORRECT option is (a) 0.15 units/s Best explanation: The distance between A and B is 10 units. The distance between B and C is 5 units. HENCE, the total distance is 15 units. The total time taken is 100 s. Average SPEED = total distance/total time taken = 15/100 = 0.15 units/s. |
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