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A body of mass 1.5kg moving with a velocity of 10m//s encounters another body of mass 2.5kg moving in opposite direction with a velocity of 16m//s, and they stick to eachother. What is the velocity of combination?

Answer»

Solution :Here, `m_(1)= 1.5kg, u_(1)= 10m//s`
`m_(2)= 2.5kg, u_(2)=16m//s`
`v=?`
Applying the principle of CONSERVATION of linear momentum,
`(m_(1)+m_(2))v=m_(1)u_(1)+m_(2)u_(2)`
`v=(m_(1)u_(1)+m_(2)u_(2))/(m_(1)+m_(2))= (1.5xx10+2.5(-16))/(1.5+2.5)= (-25)/(4.0)= -6.25m//s`
NEGATIVE sign indicates that motion of combination of BODIES is along the DIRECTION of motion of second BODY.


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