A body of mass 10 kg, projected at an angle of 30° from the ground with an initial velocity of 5 m/s, acceleration due to gravity is g = 10 m/s^2, what is the time of flight?(a) 0.866s(b) 1.86 s(c) 1.96 s(d) 1.862 sThe question was posed to me during an internship interview.Origin of the question is Simple Projectile Motion topic in chapter Motion in a Plane of Physics – Class 11

A body of mass 10 kg, projected at an angle of 30° from the ground wi

1.	A body of mass 10 kg, projected at an angle of 30° from the ground with an initial velocity of 5 m/s, acceleration due to gravity is g = 10 m/s^2, what is the time of flight?(a) 0.866s(b) 1.86 s(c) 1.96 s(d) 1.862 sThe question was posed to me during an internship interview.Origin of the question is Simple Projectile Motion topic in chapter Motion in a Plane of Physics – Class 11
Answer» The correct choice is (a) 0.866s To EXPLAIN I WOULD say: The formula for time of flight is t = 2(v sinθ/G). Here, v = 5, θ = 30°, g = 10. Hence, on solving we will GET the time of flight as 0.866 s.

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