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InterviewSolution
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A body of mass 200 kg is at rest on the earth's surface. (i) Find its gravitational potential energy . (ii) Find the kinetic energy to be provided to the body to make it free from the gravitational influence of the earth. (g = 9.8 m//s^(2) , R = 6400 km) |
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Answer» Solution :Data : m = 200 kg , g= 9.8 m`//s^(2) , R = 6400 km=6.4 xx 10^(6) m` (i) The gravitational potential of the body `- ( GMm)/R = - MGR ( therefore g = (GM)/R^(2))` ` = - 200 kg xx 9.8 m//s^(2) xx 6.4 xx 10^(6) m= - 1.2544 xx 10^(10) J` (ii) To make the body free from the gravitational influence of the earth , it should be PROVIDED KINETIC ENERGY equal to ` 1.2544 xx 10^(10)` J |
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