A body of mass 5 kg, projected at an angle of 45° from the ground covers a horizontal range of 45 m, acceleration due to gravity is g = 10 m/s^2, what is the velocity with which it was projected covered?(a) 21.21 m/s(b) 20 m/s(c) 22 m/s(d) 21.1 m/sThe question was asked in a national level competition.My doubt stems from Simple Projectile Motion topic in portion Motion in a Plane of Physics – Class 11

A body of mass 5 kg, projected at an angle of 45° from the ground cov

1.	A body of mass 5 kg, projected at an angle of 45° from the ground covers a horizontal range of 45 m, acceleration due to gravity is g = 10 m/s^2, what is the velocity with which it was projected covered?(a) 21.21 m/s(b) 20 m/s(c) 22 m/s(d) 21.1 m/sThe question was asked in a national level competition.My doubt stems from Simple Projectile Motion topic in portion Motion in a Plane of Physics – Class 11
Answer» Correct ANSWER is (a) 21.21 m/s The best I can explain: The formula for horizontal range is R = v^2 (sin 2θ)/G. Here, R = 45, θ = 45°, g = 10. Hence, on solving we will get velocity as 21.21 m/s. The result can be cross checked by putting this value of velocity and finding out the range.

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