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A body of mass 5 kg, projected at an angle of 60° from the ground with an initial velocity of 25 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum horizontal range covered?(a) 54.13 m(b) 49 m(c) 49.16 m(d) 60 mI had been asked this question by my college director while I was bunking the class.I'd like to ask this question from Simple Projectile Motion topic in portion Motion in a Plane of Physics – Class 11

Answer»

Correct choice is (a) 54.13 m

Explanation: The formula for HORIZONTAL RANGE is R = V^2 (sin 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on solving we will get range as 54.13 m.



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