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A body of mass 55 kg, projected at an angle of 45° from the ground with an initial velocity of 15 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum horizontal range covered?(a) 22.5 m(b) 25 m(c) 16 m(d) 15 mThe question was posed to me by my college professor while I was bunking the class.I'd like to ask this question from Simple Projectile Motion topic in division Motion in a Plane of Physics – Class 11 |
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Answer» CORRECT answer is (a) 22.5 m Explanation: The formula for horizontal RANGE is R = v^2 (sin 2θ)/G. Here, v = 15, θ = 45°, g = 10. Hence, on SOLVING we will get range as 22.5 m. |
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