1.

A body projected at an angle with the horizontal has a range 300 m. I the time of flight is 6s, then the horizontal component of velocity is

Answer»

30 m/s
50 m/s
40 m/s
45 m/s

Solution :`R=(U cos theta)T`
`U cos theta = (R)/(T) = (300)/(6) = 50 m//s`


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