1.

A body weight 63 N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to doubled the radius of the earth?

Answer»

Solution :Here `mg=63 N, H=2R`
As `(g_h)/(G)=((R )/(R+h))^2= ((R )/(R+R2))= (1/3)^2= (1)/(9)`
`g_(h)= (1)/(9)g`
`:. ""mg_(h)= (1)/(9)mg=(1)/(9)xx63=7N`.


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