1.

A boy lifts a mass of 300g for 1.2 second at height of 4m. What would be the power of boy? (Take g=10ms^(-2)).

Answer»

<P>`5W`
`10W`
`15W`
`20W`

Solution :`P=(W)/(t)`
`=(MGH)/(t)`
`=((0.3kg)xx(10ms^(-2))xx(4M))/(1.2s)=10W`


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