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A boy lifts a mass of 300g for 1.2 second at height of 4m. What would be the power of boy? (Take g=10ms^(-2)). |
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Answer» Solution :`P=(W)/(t)` `=(MGH)/(t)` `=((0.3kg)xx(10ms^(-2))xx(4M))/(1.2s)=10W` |
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