1.

A bulb is rated 5V, 500 mA. Calculate the rated power and resistance of the bulb when it glows.

Answer»

Solution :POTENTIAL DIFFERENCE : 5V CURRENT : 500 mA = 500 `xx10^(-3)` A
P =VI
`= 5Vxx500 xx10^(-3) A = 2.5 W `
`R = (V)/(I) = (5V)/(500xx10^(-3)A)xx10 Omega`
`R = 100 Omega`


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