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A bulb is rated 5V, 500 mA. Calculate the rated power and resistance of the bulb when it glows. |
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Answer» Solution :POTENTIAL DIFFERENCE : 5V CURRENT : 500 mA = 500 `xx10^(-3)` A P =VI `= 5Vxx500 xx10^(-3) A = 2.5 W ` `R = (V)/(I) = (5V)/(500xx10^(-3)A)xx10 Omega` `R = 100 Omega` |
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