1.

A bullet fired in to a fixed target tosses half of it's velocity after penetrating distance of 3 cm. How much further it will penetrate before coming to rest assuming that if faces constnat resistance to it's motion?

Answer»

3 cm
2.0 cm
1.5 cm
1.0 cm

Solution :`W=DeltaK`
Case I: `Fxx3=1/2m((V_(0))/2)^(2)-1/2 MV^(2)`
Where `Fto` resistive force
`V_(0)to` initial VELOCITY
Case II: Let further distance be s
`-F(3+s)=K_(f)-K_(i)=-1/2 mV_(0)^(2)`
`S=1cm`


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