1.

A bullet of a mass 0.02 kg is moving with a speed of 10ms^(-1). It can penetrate 10 cm of a wooden block, and comes to rest. If the thickness of the target would be 6 cmonly, find the K.E. of the bullet when it comes out.

Answer»

SOLUTION :For x=10cm =0.1 m `Fx=1/2mv_(1)^(2)=1J`
`:.F=10N`
For x=6cm=0.06m,`Fx=1/2mv_(1)^(2)-1/2mv_(2)^(2)`
or `Fx=1/2mv_(1)^(2)-` FINAL K.E.
or Final K.E.`=1/2mv_(1)^(2)-Fx=1-10xx0.06`
`=1-0.6`
`=0.4J`


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