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A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg . What is the recoil velocity of the pistol ? |
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Answer» SOLUTION :Bullet `m_1` mass =20G =0.02 kg `u_1=0` `v_1 =150m//s` PISTOL `m_2 =2 kg ` `u_2=0` `v_2=?` Total MOMENTUM of the pistol and bullet before firing, when the gun is at rest `=m_1u_1+m_2u_2` `=(0.02 xx0)+(2xx0)` Total momentum of the pistol and bullet after it is fires. `=m_1v_1+m_2v_2` `=(0.02xx150)+(2xxv)` `=3+2 v` Therefore Total mementum after firing = Total moment before firing 3+2v=0 V=-3/2 =-1.5 m/s |
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