1.

A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg . What is the recoil velocity of the pistol ?

Answer»

SOLUTION :Bullet
`m_1` mass =20G
=0.02 kg
`u_1=0`
`v_1 =150m//s`
PISTOL
`m_2 =2 kg `
`u_2=0`
`v_2=?`
Total MOMENTUM of the pistol and bullet before firing, when the gun is at rest
`=m_1u_1+m_2u_2`
`=(0.02 xx0)+(2xx0)`
Total momentum of the pistol and bullet after it is fires.
`=m_1v_1+m_2v_2`
`=(0.02xx150)+(2xxv)`
`=3+2 v`
Therefore Total mementum after firing = Total moment before firing
3+2v=0
V=-3/2 =-1.5 m/s


Discussion

No Comment Found

Related InterviewSolutions