1.

A bullet of mass m moving with a speed v strikes a wooden block of mass M & gets embedded into the block. The final speed is

Answer»

`sqrt((M)/(M+n))V`
`sqrt((m)/(M+n))V`
`(m)/(M+n) V`
`V/2`

Solution :By LAW of conservation of momentum
mv+M(0)=(m+M)V
`V=(mv)/(m+M)`


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