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A bus decreases its speed from 80 km h^(-1) to 60 km h^(-1) in 5s. Find the acceleration of the bus. |
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Answer» Solution :Initial speed of the bus `(u) = 80 km h ^(-1)` `= ( 80 XX 1000)/( 3600) ms ^(-1)` `= (800)/(36) ms ^(-1)` FINAL speed of the bus `(v) =60 kmh^(1)` `= (60 xx 1000)/( 3600) ms ^(-1)` `= (600)/(36) ms ^(-1)` Acceleration `= (u-v)/(t) = ((600)/(36)- (800)/(36))/( 5) = (-200)/( 36) xx 1/5 =- (10)/(9) ~~-1.11 ms ^(-2)` The acceleration of the bus is `-1.11 ms ^(-2)` `(or -1.11 ms ^(-2))` |
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