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A bus is moving with the initial velocity of 'u' m/s. After applying the breaks, its retardation is 0.5 m/s^(2) and it stoped after 12s. Find the initial velocity (u) and distance travel by the bus after applying the breaks. |
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Answer» Solution :a = 0.5 `m//s^(2)` v = 0 m/s t = 12 s u = ? v = u + at 0 = u + `(-0.5 XX 12 )` 0 = u- 6 u = 6 m/s INITIAL velocity of the bus 6 m/s . s = ut + `(1)/(2) at^(2)` = `( 12 xx 6 ) + (1)/(2) ( - 0.5 xx 12^(2) )` = 72 -` (1)/(2) (72)` = 36 m Bus has stoped 36 m distance after applying the break |
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