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A capacitor charges from a cell through a resistance. The time constant is `tau`. In what time will the capacitor collect `10%` of the final charge?A. `tau 1n (0.1)`B. `tau 1n (0.9)`C. `tau 1n 10/9`D. `tau 1n 11/10` |
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Answer» Correct Answer - C `q = q_(0) (1-e^(-t//tau))` `1/10 q_(0)=q_(0) (1-e^(-t//tau))implies e^(-t//tau) = 9/10` `e^(-t//tau)=10//9` `t/(tau) 1n e = 1n(10//9)` `t=tau 1n(10//9)`. |
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