1.

The expression for thermo emf in a thermocouple given by the relation `E=40theta-(theta^(2))/(20)`, where `theta` is the temperatue difference of two junctons. For this, the neutral temperature will beA. `100^@C`B. `200^@C`C. `300^@C`D. `400^@C`

Answer» Correct Answer - D
`E = 40 theta -(theta^2)/(20)`
For neutral temperature.
`(dE)/(d theta) = 40-(theta)/(10)=0 implies theta = 400^(@)C`.


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