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The cold junction of a thermocouple is maintained at `15^(@)C`. No thermo-emf is developed when the hot junction is mainted at `525^(@)C` . Find neutral temperature. |
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Answer» Since `E=0` then `T_(i) = 525^(@)C` `T_(c) = 15^@C` `T_(i) - T_(n) = T_(n)-T_(c)` `T_(n) = (T_(i)+T_(c))/(2) = (525+15)/(2) = 270^@C`. |
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