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Thermoelectric constant of a thermocouple are `alpha` and `beta`. Thermoelectric power at inversion tempreture isA. `alpha`B. `- alpha`C. `(alpha)/(beta)`D. `-(alpha)/(beta)`

Answer» Correct Answer - B
`E = alpha T + 1/3 beta T^(2)`
For inversion temperature
`E = 0, T_(i) = -(2alpha)/(beta)`
Thermoelectric power ltbr. `P = (dE)/(dT) = alpha + 1/2 beta.(2T) = alpha+beta T_(i)`
`alpha+beta(-(2alpha)/(beta))=-alpha`.


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