A capacitor of capacitance 50 μF is connected in parallel to another capacitor of capacitance 100 μF. They are connected across a time-varying voltage source. At a particular time, the current supplied by the source is 5 A. The magnitude of instantaneous current through the capacitor of capacitance 50 μF is?(a) 1.57 A(b) 1.87 A(c) 1.67 A(d) 2.83 AI have been asked this question in an online interview.The query is from Problems Involving Dot Conventions in section Resonance & Magnetically Coupled Circuit of Network Theory

A capacitor of capacitance 50 μF is connected in parallel to another

1.	A capacitor of capacitance 50 μF is connected in parallel to another capacitor of capacitance 100 μF. They are connected across a time-varying voltage source. At a particular time, the current supplied by the source is 5 A. The magnitude of instantaneous current through the capacitor of capacitance 50 μF is?(a) 1.57 A(b) 1.87 A(c) 1.67 A(d) 2.83 AI have been asked this question in an online interview.The query is from Problems Involving Dot Conventions in section Resonance & Magnetically Coupled Circuit of Network Theory
Answer» Correct ANSWER is (c) 1.67 A Explanation: As the CAPACITORS are in parallel, then the voltage V is given by, V = \(\frac{1}{C_1}\int I_1\,dt \) ∴ I1 = C1 \(\frac{dV}{dt}\) That is, \(\frac{I_1}{I_2}= \frac{C_1}{C_2}= \frac{50}{100} = \frac{1}{2}\) ………………….. (1) Also, I1 + I2 = 5 A ………………………….. (2) Solving (1) and (2), we get, I1 = 1.67 A.

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