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A car initially at rest starts moving with a constant acceleration of 0.5 m s^(-2) and travels a distance of 25 m. Find : (i) its final velocity and (ii) the time taken. |
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Answer» Solution :Given initial velocity u =0 acceleration a= 0.5 m `s^(-2)` Distance TRAVELLED S = 25 m. (i) From equation of motion `v^(2) = u^(2)+2AS` `v^(2) = (0)^(2) +2 xx0.5xx25` or `v^(2) =25` or Final velocity v = `SQRT(25) = 5 m s^(-1)` (ii) From equation of motion v = u + at 5 =0 +0.5 `xx`tor 0.5 t =5 `:.` TIME taken t `= (5)/(0.5)` = 10 s. |
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