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A car moving at `160 km//h` when passes the mark-A, driver applies brake and reduces its speed uniformly to `40 km//h` at mark-C. The mark are spaced at equal distances along the road as shown below. At which part of the track the car has instantaneous speed of `100 km//h` ? Neglect the size of the car. A. A mark-BB. Between mark-A and mark-BC. between mark-B and mark-CD. insufficient information to decide. |
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Answer» Correct Answer - C From `A` to `C` : `(40)^2 - (160)^2 = 2a (AC)` From `A` to `D` : `(100)^2 - (160)^2 = 2a (AD)` Here `D` is the point where speed is `100 km//h`. From above `AD = (13)/(20) (AC) and AB = (AC)/(2)` We see that AD gt AB`. |
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