A particle starts from rest with uniform acceleration and is velocity after `n` seconds `v`. The displacement of the body in last two seconds is.A. `(2v(n + 1))/(n)`B. `(v(n + 1))/(n)`C. `(v(n - 1))/(n)`D. `(2 v(n - 1))/(n)`

A particle starts from rest with uniform acceleration and is velocity

1.	A particle starts from rest with uniform acceleration and is velocity after `n` seconds `v`. The displacement of the body in last two seconds is.A. `(2v(n + 1))/(n)`B. `(v(n + 1))/(n)`C. `(v(n - 1))/(n)`D. `(2 v(n - 1))/(n)`
Answer» Correct Answer - D `because v = 0 + na rArr a = (v)/(n)` Now, distance travelled in `n sec` `rArr S_n = (1)/(2) an^2` and distance travelled in `(n - 2) sec` `rArr S_(n - 2) = (1)/(2) a(n - 2)^2` `:.` Distance travelled in last two seconds =`S_n - S_(n - 2)` =`(1)/(2) an^2 - (1)/(2) a(n - 2)^2` =`(a)/(2)[n^2 - (n - 2)^2]` =`(a)/(2)[n + (n - 2)][n -(n - 2)]` =`a(2 n - 2)` =`(v)/(n)(2n - 2) = (2v(n - 1))/(n)`.

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