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Speeds of two identical cars are u and 4u at at specific instant. The ratio of the respective distances in which the two cars are stopped from that instant isA. `1 : 1`B. `1 : 4`C. `1 : 8`D. `1 : 16` |
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Answer» Correct Answer - D Using `v^2 = u^2 + 2as`. If car is retarding and final velocity becomes zero. Then, the equation becomes `0 = u^2 - 2as rArr s = (u^2)/(2a)` or `s prop u^2` As `s prop u^2 rArr (s_1)/(s_2) = ((1)/(4))^2 = (1)/(16)`. |
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