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If the velocity of a particle is `v = At + Bt^2`, where `A` and `B` are constant, then the distance travelled by it between `1 s` and `2 s` is :A. `(3)/(2) A + 4B`B. `3 A + 7 B`C. `(3)/(2)A + (7)/(3) B`D. `(A)/(2) + (B)/(3)` |
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Answer» Correct Answer - C `V = At + Bt^2 rArr (dx)/(dt) = At + Bt^2` `rArr underset(0)overset(x)(int) dx = underset(1)overset(2)(int)(At + Bt^2) dt` `rArr x = (A)/(2) (2^2 - 1^2) + (B)/(3)(2^3 - 1^3) =(3 A)/(2) + (7 B)/(3)`. |
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