InterviewSolution
Saved Bookmarks
| 1. |
A body `A` starts from rest with an acceleration `a_1`. After `2` seconds, another body `B` starts from rest with an acceleration `a_2`. If they travel equal distances in the `5th` second, after the start of `A`, then the ratio `a_1 : a_2` is equal to :A. `5 : 9`B. `5 : 7`C. `9 : 5`D. `9 : 7` |
|
Answer» Correct Answer - A According to problem Distance travelled by body `A` in `5^(th) sec` and distance travelled by body `B` in `3^(rd) sec` of its motion are equal. `0 + (a_1)/(2)(2 xx 5 - 1) = 0 + (a_2)/(2)[2 xx 3 - 1]` `9 a_1 = 5 a_2 rArr (a_1)/(a_2) = (5)/(9)`. |
|