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A certain mass of a gas occupies a volume of 600 mL at a certain temperature andperssure. If the temperature is increased by 80% whatwill be the volume occupied by thesame mass of gas at thesame pressure? |
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Answer» 1080mL Initial temperature, `T_(1) = x` Final temperature, `T_(2) = (180x)/100` Final volume, `V_(2)` = ? `V_(1)/T_(1) = V_(2)/T_(2) ` as per Charles' LAW `600/x = (V_(2) xx 100)/(180x) = V_(2) = 1080` mL |
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