1.

A certain mass of a gas occupies a volume of 600 mL at a certain temperature andpressure. If pressure is decreased by 40% what will be the volume occupied by thesame mass of the gas at the same temperature ?

Answer»

240 mL
1000mL
300mL
120 mL

Solution :INITIAL VOLUME, ` V_(1) = 600` mL
Let initial pressure be `P_(1) = x`
Finalpressure, `P_(2) = (60x)/100 `
Final volume, `V_(2)`
As per Boyle's law,` P_(1)V_(1) = P_(2)V_(2) rArr V_(2) = (P_(1)V_(1))/P_(2)`
`V_(2) = (x xx 600 xx 100)/(60 x)`
` V_(2) = 1000`mL


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