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A certain mass of a gas occupies a volume of 600 mL at a certain temperature andpressure. If pressure is decreased by 40% what will be the volume occupied by thesame mass of the gas at the same temperature ? |
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Answer» 240 mL Let initial pressure be `P_(1) = x` Finalpressure, `P_(2) = (60x)/100 ` Final volume, `V_(2)` As per Boyle's law,` P_(1)V_(1) = P_(2)V_(2) rArr V_(2) = (P_(1)V_(1))/P_(2)` `V_(2) = (x xx 600 xx 100)/(60 x)` ` V_(2) = 1000`mL |
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