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A certain radioactive material can undergo three constant `lambda,2lambda` and `3 lambda`. Then, the effective decay constant `lambda_(eff)` is equal to `n lambda`. What is the value of n? |
Answer» Correct Answer - 6 Effective decay constant will be sum of all different decay constant So, `lambda_(eff)=lambda+2lambda+3lambda=6lambda,`hence `n=6`. |
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