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A certain radioactive material can undergo three constant `lambda,2lambda` and `3 lambda`. Then, the effective decay constant `lambda_(eff)` is equal to `n lambda`. What is the value of n?A. ` 6 lambda`B. ` 4 lambda`C. `2 lambda`D. ` 3 lambda` |
Answer» Correct Answer - a `(dN_(A))/(dt)=(- lambda N_(A))+(- 2 lambda N_(A)) +(-2 lambdaN_(A))=-6 lambda N_(A)`. |
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