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A certain transition emits `6.37 xx 10^(15)` quats per second per square .Calculate the power out put in joule equare metre per second .Given `lambda = 632.8 nm` |
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Answer» Energy failing per aqure metre per second is .Number of quanta falling per metre second xx Energy of one question `= 6.37 xx 10^(15) xx (hc)/(lambda)` `= 6.37 xx 10^(12) xx (6.25 xx 10^(-34) xx 3 xx 10^(8))/(632.6 xx 10^(-6))` `= 2 xx 10^(-3) J m^(-1)s^(-1)` |
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