InterviewSolution
Saved Bookmarks
| 1. |
A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: `lamda=(h)/(sqrt(2qVm))` where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: `lamda=(12.3)/(sqrt(V))`Ã… Q. In order to get half velocity of electrons in second case, the applied potential will be:A. 0.25 kVB. 2 kVC. 0.5 kVD. 0.75 kV |
| Answer» Correct Answer - a | |