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A circuit with a resistor, inductor and capacitor in series is resonant with frequency f Hz. If all the component values are now doubled, then the new resonant frequency will be?(a) 2 f(b) f(c) \(\frac{f}{4}\)(d) \(\frac{f}{2}\)I got this question during a job interview.My query is from Problems of Series Resonance Involving Frequency Response of Series Resonant Circuit in section Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct answer is (d) \(\frac{f}{2}\)

The BEST I can explain: Resonance FREQUENCY = \(\frac{1}{2π\sqrt{LC}} = \frac{1}{2π2\sqrt{LC}}\)

Hence, \(\frac{f}{f_o}= \frac{\frac{1}{2π\sqrt{LC}}}{\frac{1}{2π2\sqrt{LC}}}\) = 2

∴ f = 2fo.



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