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A cistern 5 m long and 8 m wide, contains water up to depth of 2 m 45 cm. Find the total area of wet surface.1). 103 m22). 103.7 m23). 92 m24). 82.80 m2 |
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Answer» A cistern 5 m long and 8 m wide, CONTAINS water up to depth of 2 m 45 cm. Here, cistern is in cuboid form Length of cistern = 5 m Breadth of cistern = 8 m HEIGHT of cistern upto which its WET = 2 m 45 cm = 2.45 m Total area of wet SURFACE = {2(length + breadth) × height} + (length × breadth) = {2(5 + 8) × 2.45} + (5 × 8) = 63.7 + 40 =103.7 m2 |
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