1.

A cistern 5 m long and 8 m wide, contains water up to depth of 2 m 45 cm. Find the total area of wet surface.1). 103 m22). 103.7 m23). 92 m24). 82.80 m2

Answer»

A cistern 5 m long and 8 m wide, CONTAINS water up to depth of 2 m 45 cm.

Here, cistern is in cuboid form

Length of cistern = 5 m

Breadth of cistern = 8 m

HEIGHT of cistern upto which its WET = 2 m 45 cm = 2.45 m

Total area of wet SURFACE = {2(length + breadth) × height} + (length × breadth)

= {2(5 + 8) × 2.45} + (5 × 8)

= 63.7 + 40

=103.7 m2


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