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InterviewSolution
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A coin kept inside water (mu=4//3) when viewed from air in a vertical direction, appears to be raised by 2*0mm. Find the depth of the coin in water. |
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Answer» Solution :Given: `mu=(4)/(3)`, shift=`2*0mm` Let REAL depth be x mm. then Apparent depth`=(x)/(mu)=(x)/(4//3)=(3)/(4)x` Shift=real depth-apparent depth `=x-(3)/(4)x=(1)/(4)x` Given shift `(1)/(4)x=2*0mm""thereforex=8*0mm` Thus depth of coin in water=`8*0`mm. |
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