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A complex of iron and cyanide ions is `100%`ionised ar `1`m (molal). If its elevation in b.p.is `2.08` then the complex is `(K_(b)=0.52^(@)mol^(-1)kg)`,A. `K_(3)[Fe(CN)_(6)]`B. `Fe(CN)_(2)`C. `K_(4)[Fe(CN)_(6)]`D. `Fe(CN)_(4)` |
Answer» Correct Answer - A `DeltaT_(b)=iK_(b)m` so `i=(2.08)/(0.52xx1)=4` so the compex is `K_(3)[Fe(CN)_(6)]` `K_(3)[Fe(CN)_(6)]hArr3K^(+)+[Fe(CN)_(6)]^(3-)` |
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