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A compound C (molecular formula, C_(2)H_(4)O_(2)) reacts with Na-metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S (molecular formula C_(3)H_(6)O_(2)). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A. Identify C, R, A, S and write down the reactions involved. |
Answer» Solution :C - Ethanoic acid R - Sodium salt of ethanoic acid (sodium acetate) and gas evolved is HYDROGEN A - Methanol S - Ester (Methyl acetate) (a) `underset((C )) (2CH_(3)COOH)+2NA to underset((R ))(2CH_(3)COONa)+H_(2)` (b) `underset((C ))(CH_(3)COOH)+underset((A))(CH_(3)OH) overset("CONC. "H_(2)SO_(4)) to underset((S))(CH_(3)COOCH_(3))+H_(2)O` (c )` underset((C ))(CH_(3)COOH)+NaOH overset("Conc. "H_(2)SO_(4))to underset((R )) (CH_(3)COONa)+H_(2)O` (d) `underset((S))(CH_(3)COOCH_(3))+NaOH to underset((R ))(CH_(3)COONa)+underset((A))(CH_(3)OH)` |
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