1.

A compound consists of 47.8% zinc and 52.2% chlorine by mass. The empirical formula is Zn_x Cl_ywhere x and y can have the values

Answer»

1 and 1
1 and 2
2 and 1
2 and 3 respectively

Solution :NUMBER of MOLES of Zn: Number of moles of CL
` = (47.8)/(65) : (52.2)/(35.5)`
`= 0.735 : 1.470`
`= 1:2`
Empirical formula is `Zn_1Cl_2`
X = 1 and y = 2


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