1.

A compound of vanadium has a magnetic moment of `1.73BM`. Work out the electronic configuration of vanadium in the compoundA. `[Ar]3d^(1)`B. `[Ar]3d^(2)`C. `[Ar]3d^(3)`D. `[Ar]3d^(0)`

Answer» Correct Answer - A
`sqrt(n(n+2))=1.73`
`n(n+2)=3`
`n=1`
So vandium has 1 unparied electron and its configuration is`[A]3d^(1)`.


Discussion

No Comment Found

Related InterviewSolutions