1.

A conductor of length 50 cm carrying a current of 5A is placed perpendicular to a magnetic fieldof induction 2xx10^(-3) T. Find the force on the conductor.

Answer»

SOLUTION :Force on the conductro `=ILB`
`=5x50xx10^(-2)xx2xx10^(-3)`
`=5XX10^(-3)N`


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