1.

A cone of equal height and equal base is cut off from a cylinder of height 24 cm and base radius 7 cm .Find the total surface and volume of remaining solid.

Answer»

Solution :Here r=7 cm,H =24 cm
volume of remaining solid =volume of cylinder -volume of CONE
`=pir^(2)h-(1)/(3)PI^(2)h=(2)/(3)pir^(2)h`
`=(2)/(3)XX(22)/(7)xx7xx24=2464 cm^(3)` ltbr Noo , l^(2)=h^(2)+r^(2)=(24)^(2)+(7)^(2)`
`=576+49=625`
l=25cm
Total surface area of remaining solid
=curved surface of cylinder + curved surface of cone +area of top
`=2pirh+pirl+pir^(2)`
`=pir(2h+l+r)`
`1=(22)/(7)xx7(2xx24+25+7)=22xx80=1760 cm^(2)`


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