InterviewSolution
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A container contains some amount of milk. A milkman adds 200 ml of water for each one litre of milk in the container. 12 litres of the mixture is sold from the container and 20 litres of milk is added to the remaining mixture. If now the ratio of milk to water in container is 25 : 3, find the initial quantity of milk in the container.1). 35 liters2). 24 liters3). 40 liters4). 30 liters |
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Answer» LET initial QUANTITY of milk = 10x liters, For each 1 liter, 200 ml of water is added, So for 10x liters 2x liters of water is added RATIO of milk and water = 10x ? 2x = 5 ? 1 So after adding water, quantity of mixture become = 12x liters Now 12 liters of mixture is sold, and 20 liters of milk is added So remaining quantity is (12x – 12 + 20) = (12x + 8) Quantity of milk sold = $(12{\rm{\;}} \times {\rm{\;}}\frac{5}{6} = 10)$ In this final quantity, milk = 10x – 10 + 20 = (10x + 10) The ratio of milk to water in container is 25 : 3 $(\frac{{10{\rm{x}} + 10}}{{12{\rm{x}} + 8}} = {\rm{\;}}\frac{{25}}{{28}})$ ⇒ 28 × (10x + 10) = 25 × (12x + 8) ⇒ 280x + 280 = 300x + 200 ⇒ 20X = 80 ⇒ x = 4So initial quantity of milk = 10x = 40 liters |
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