1.

A cook uses a fire tongs of length 28 cm to lift a piece of burning coal of mass 250 g. if he applies effort at a distance of 7 cm from the fulcrum, find the effort. Take g=10ms^(-2).

Answer»

Solution :The fire tongs is a lever of class III which has fulcrum and LOAD at the ends, with effort in between.
Given :
Load L=250 GF=`0*25kgf=0*25xx10N=2*5N`,
laod arm =28cm, effort arm=7cm
By the principle of moments.
load`xx`load arm=effort`xx`effort arm
`therefore`effort=load`xx("load arm")/("effort arm")=2*5xx(28)/(7)=10N`.


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