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A cook uses a fire tongs of length 28 cm to lift a piece of burning coal of mass 250 g. if he applies effort at a distance of 7 cm from the fulcrum, find the effort. Take g=10ms^(-2). |
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Answer» Solution :The fire tongs is a lever of class III which has fulcrum and LOAD at the ends, with effort in between. Given : Load L=250 GF=`0*25kgf=0*25xx10N=2*5N`, laod arm =28cm, effort arm=7cm By the principle of moments. load`xx`load arm=effort`xx`effort arm `therefore`effort=load`xx("load arm")/("effort arm")=2*5xx(28)/(7)=10N`. |
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