1.

A copper wire is bent in the form of an equilateral triangle and has area 121√3 cm2. If the same wire is bent into the form of a circle, the area (in cm2) enclosed by the wire is \(\left( {Take\;\pi= \frac{{22}}{7}} \right)\)1). 364.52). 693.53). 346.54). 639.5

Answer»

⇒ Let the side of an equilateral TRIANGLE be a

⇒ Area of equilateral triangle = (√3 a2)/4

121√3 = (√3 a2)/4

⇒ a2 = 121 × 4

⇒ a = 22

⇒ Total length of wire = 3A = 3 × 22

⇒ Total length of wire = 66

⇒ when it bent into CIRCLE then circumference = 66

⇒ 2πr = 66

⇒ r = (33/22) × 7

⇒ r = 10.5 cm

⇒ Area = πr2

⇒ Area = (22/7) × 10.52

⇒ Area = 346.5


Discussion

No Comment Found

Related InterviewSolutions