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A copper wire is bent in the form of an equilateral triangle and has area 121√3 cm2. If the same wire is bent into the form of a circle, the area (in cm2) enclosed by the wire is \(\left( {Take\;\pi= \frac{{22}}{7}} \right)\)1). 364.52). 693.53). 346.54). 639.5 |
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Answer» ⇒ Let the side of an equilateral TRIANGLE be a ⇒ Area of equilateral triangle = (√3 a2)/4 ⇒ 121√3 = (√3 a2)/4 ⇒ a2 = 121 × 4 ⇒ a = 22 ⇒ Total length of wire = 3A = 3 × 22 ⇒ Total length of wire = 66 ⇒ when it bent into CIRCLE then circumference = 66 ⇒ 2πr = 66 ⇒ r = (33/22) × 7 ⇒ r = 10.5 cm ⇒ Area = πr2 ⇒ Area = (22/7) × 10.52 ⇒ Area = 346.5 |
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